So I have already implemented every part of a Hough Transform on my own, except for actually plotting the lines back onto the original image.

I can set up my array of data that I have like this.

```
points | theta | rho
-------|-------|----
[246,0] -90 -246
[128,0] -90 -128
[9,0] -90 -9
[0,9] 0 9
[0,128] 0 128
[0,246] 0 246
```

The points are the points that were converted **from** the peaks in Polar Coordinates. So now I need to draw all six of these lines and I have had no luck.

Edit

So I tried to change my code based off suggestions. This is what I came up with.

```
function help(img, outfile, peaks, rho, theta)
imshow(img);
x0 = 1;
xend = size(img,2);
peaks_len=length(peaks);
for i=1:peaks_len
peak=peaks(i,:);
r_ind=peak(1);
t_ind=peak(2);
r=rho(r_ind);
th=theta(t_ind);
%display([r,th,peak]);
%// if a vertical line, then draw a vertical line centered at x = r
% display([r, th]);
if (th == 0)
display('th=0');
display([1, size(img,1)]);
line([r r], [1 size(img,1)], 'Color', 'green');
else
%// Compute starting y coordinate
y0 = abs((-cosd(th)/sind(th))*x0 + (r / sind(th)))+11;%-25;
%// Compute ending y coordinate
yend = abs((-cosd(th)/sind(th))*xend + (r / sind(th)))+11;%-25;
display('y');
display([y0, yend]);
display('x');
display([x0 xend]);
%// Draw the line
line([x0 xend], [y0 yend], 'Color', 'green');
end
end
end
```

I had to change from `r==0`

to `th==0`

because `th=0`

would give `NAN`

errors when r was not 0.

Based off the peaks, I then used that to get the data I needed to then calculate some values… but for some reason this isn’t plotting well.

If you notice the + 11 for both y values. I had to do that to get the lines to be where they need to. I have a feeling something else went wrong.

I did change it so that my Rho values are all now positive.

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